Concentration increase and product mass
A soluble fertilizer calculation starts with the increase in one nutrient concentration. Any concentration already present in the water is subtracted first. The total nutrient mass is then divided by the product’s mass fraction of that nutrient.
Measure and calculate
- Enter target and starting concentration for the same nutrient in mg/L.
- Enter the water volume in US gallons and product nutrient fraction.
- Check that the target is at least the starting concentration before calculating grams of product.
Product grams = (target − starting mg/L) × US gallons × 3.785411784 ÷ 1,000 ÷ nutrient fraction.
A worked example
- Inputs
- Five US gallons of water start at 0 mg/L; the example target is 100 mg/L using a 20% nutrient product.
- Calculation
100 × 5 × 3.785411784 ÷ 1,000 ÷ 0.20 = 9.46352946 g.- Result
- 9.46 g
The displayed result is 9.46 g of product for this arithmetic scenario. It is not a feeding recommendation and does not model other ingredients or mixing compatibility.
Read the result
| Output or check | What it means for your project |
|---|---|
| Product mass: g | The calculation uses the difference between target and starting concentration, water volume and the fraction of the selected nutrient. |
| Concentration boundary | Equal target and starting concentrations give zero added product. A target below the starting level is outside this addition-only calculation; changing concentrations requires a different approach. |
Common questions
Why subtract the starting concentration?
The nutrient already in the water contributes to the final target. Ignoring it can overstate the required addition.
Can adding fertilizer reduce a concentration?
Not in this model. A target below the starting concentration is rejected because addition alone cannot achieve that reduction.
